3u^2-19u+16=0

Solution for 3u^2-19u+16=0 equation:

Simplifying
3u2 + -19u + 16 = 0

Reorder the terms:
16 + -19u + 3u2 = 0

Solving
16 + -19u + 3u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(1 + -1u)(16 + -3u) = 0

Subproblem 1
Set the factor '(1 + -1u)' equal to zero and attempt to solve:

Simplifying
1 + -1u = 0

Solving
1 + -1u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1u = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1u = 0 + -1
-1u = 0 + -1

Combine like terms: 0 + -1 = -1
-1u = -1

Divide each side by '-1'.
u = 1

Simplifying
u = 1
Subproblem 2
Set the factor '(16 + -3u)' equal to zero and attempt to solve:

Simplifying
16 + -3u = 0

Solving
16 + -3u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -3u = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -3u = 0 + -16
-3u = 0 + -16

Combine like terms: 0 + -16 = -16
-3u = -16

Divide each side by '-3'.
u = 5.333333333

Simplifying
u = 5.333333333
Solution
u = {1, 5.333333333}